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-rw-r--r--sql.html.markdown24
1 files changed, 12 insertions, 12 deletions
diff --git a/sql.html.markdown b/sql.html.markdown
index 200f4f98..392b0edf 100644
--- a/sql.html.markdown
+++ b/sql.html.markdown
@@ -27,7 +27,7 @@ DROP DATABASE someDatabase;
SHOW DATABASES;
-- Use a particular existing database.
-USE employees;
+USE employees;
-- Select all rows and columns from the current database's departments table.
-- Default activity is for the interpreter to scroll the results on your screen.
@@ -43,12 +43,12 @@ SELECT dept_no,
SELECT * FROM departments LIMIT 5;
-- Retrieve dept_name column values from the departments
--- table where the dept_name value has the substring "en".
-SELECT dept_name FROM departments WHERE dept_name LIKE "%en%";
+-- table where the dept_name value has the substring 'en'.
+SELECT dept_name FROM departments WHERE dept_name LIKE '%en%';
-- Retrieve all columns from the departments table where the dept_name
--- column starts with an "S" and has exactly 4 characters after it.
-SELECT * FROM departments WHERE dept_name LIKE "S____";
+-- column starts with an 'S' and has exactly 4 characters after it.
+SELECT * FROM departments WHERE dept_name LIKE 'S____';
-- Select title values from the titles table but don't show duplicates.
SELECT DISTINCT title FROM titles;
@@ -60,8 +60,8 @@ SELECT DISTINCT title FROM titles ORDER BY title;
SELECT COUNT(*) FROM departments;
-- Show the number of rows in the departments table that
--- have "en" as a substring of the dept_name value.
-SELECT COUNT(*) FROM departments WHERE dept_name LIKE "%en%";
+-- have 'en' as a substring of the dept_name value.
+SELECT COUNT(*) FROM departments WHERE dept_name LIKE '%en%';
-- A JOIN of information from multiple tables: the titles table shows
-- who had what job titles, by their employee numbers, from what
@@ -89,13 +89,13 @@ CREATE TABLE tablename1 (`fname` VARCHAR(20),`lname` VARCHAR(20));
-- table has been defined to accept these values as appropriate for it.
INSERT INTO tablename1 VALUES('Richard','Mutt');
--- In tablename1, change the fname value to "John"
--- for all rows that have an lname value of "Mutt".
-UPDATE tablename1 SET fname="John" WHERE lname="Mutt";
+-- In tablename1, change the fname value to 'John'
+-- for all rows that have an lname value of 'Mutt'.
+UPDATE tablename1 SET fname='John' WHERE lname='Mutt';
-- Delete rows from the tablename1 table
--- where the lname value begins with "M".
-DELETE FROM tablename1 WHERE lname like "M%";
+-- where the lname value begins with 'M'.
+DELETE FROM tablename1 WHERE lname like 'M%';
-- Delete all rows from the tablename1 table, leaving the empty table.
DELETE FROM tablename1;