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author | Sriram Sundarraj <sriram.s.1994@gmail.com> | 2015-04-24 02:36:54 +0530 |
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committer | Sriram Sundarraj <sriram.s.1994@gmail.com> | 2015-04-24 02:36:54 +0530 |
commit | 19f6739cbaa06b6b40b835115a0361f5e77bd0e0 (patch) | |
tree | 1c9fdef566ae41f14779127649969b1b9a76f758 | |
parent | 04eed19763b7aad50318212f96e98860a38735af (diff) |
[bash/en] Fixed overflowing line.
-rw-r--r-- | bash.html.markdown | 6 |
1 files changed, 4 insertions, 2 deletions
diff --git a/bash.html.markdown b/bash.html.markdown index 3b163638..35bed9a2 100644 --- a/bash.html.markdown +++ b/bash.html.markdown @@ -235,11 +235,13 @@ uniq -d file.txt cut -d ',' -f 1 file.txt # replaces every occurrence of 'okay' with 'great' in file.txt, (regex compatible) sed -i 's/okay/great/g' file.txt -# print to stdout all lines of file.txt which match some regex, the example prints lines which begin with "foo" and end in "bar" +# print to stdout all lines of file.txt which match some regex +# The example prints lines which begin with "foo" and end in "bar" grep "^foo.*bar$" file.txt # pass the option "-c" to instead print the number of lines matching the regex grep -c "^foo.*bar$" file.txt -# if you literally want to search for the string, and not the regex, use fgrep (or grep -F) +# if you literally want to search for the string, +# and not the regex, use fgrep (or grep -F) fgrep "^foo.*bar$" file.txt |