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| author | Jake Prather <JakeHP@Zoho.com> | 2015-02-01 11:14:48 -0600 |
|---|---|---|
| committer | Jake Prather <JakeHP@Zoho.com> | 2015-02-01 11:14:48 -0600 |
| commit | 26c7b45feb80bf1aa456e8e75a6087288e57ca10 (patch) | |
| tree | 96de0c09680352353e9eba16b1c5dc3ff5b587a0 /asymptotic-notation.html.markdown | |
| parent | 4380245292e64ca22cd5cc6927ac146815914681 (diff) | |
formatting - removed italics
Diffstat (limited to 'asymptotic-notation.html.markdown')
| -rw-r--r-- | asymptotic-notation.html.markdown | 4 |
1 files changed, 2 insertions, 2 deletions
diff --git a/asymptotic-notation.html.markdown b/asymptotic-notation.html.markdown index ba665a95..3ed1a25a 100644 --- a/asymptotic-notation.html.markdown +++ b/asymptotic-notation.html.markdown @@ -97,9 +97,9 @@ g(n) = n ``` is f(n) O(g(n))? -is 3*n^2 O(n)? +is 3 * n^2 O(n)? Let's look at the definition of Big-Oh. -3*n^2 <= c * n +3 * n^2 <= c * n Is there some constant c that satisfies this for all n? No there isn't, f(n) is NOT O(g(n)). |